40x^2-2x-126=0

Solution for 40x^2-2x-126=0 equation:

40x^2-2x-126=0

a = 40; b = -2; c = -126;
Δ = b2-4ac
Δ = -22-4·40·(-126)
Δ = 20164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20164}=142$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-142}{2*40}=\frac{-140}{80}
=-1+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+142}{2*40}=\frac{144}{80}
=1+4/5
$